Find the kinetic energy, potential energy and total energy in
first and second orbit of hydrogen atom if potential energy in first orbit is taken
to be zero.

Explanation

`E_(1)=-13.60eV, K_(1)=-E_(1)=13.60eV`
`U_(1)=2E_(1) =-27.20eV E_(2)=-3.40eV K_(2) =`
`3.40eV` and `U_(2) =-6.80eV `
Now , `U_(1) =0` ,i.e potential energy has been increased by `27.20e` v . So , we will increased U and `E` in all energy states by `27.20 eV` while kitnetic energy will remain unchanged.
Hence `K(eV) , U(eV), E(eV)`
`{:("First orbit are",13.6,0,13.6),("in second orbit",3.40,20.40,23.80):}`