The radius of innermost electron orbit of a hydrogen atom is `5.3xx10^(-11)m`. What are the radii of n=2 and n=3 orbits.?

Explanation

Given , the radius of the innermost electron orbits of a hydrogen `r=5.3xx10^(-11)x`.
as we know that
` r_(n)=(n^2)r_(1)` for `n=2`, radius `r_(2)=2^(2 )`
` r_(1)=4xx5.3xx10^(-11)=2.12xx10^(-10)m`.
for` n=3`, Radius `r_(3)=3^(2)`
`r_(1)=9xx5.3xx10^(-11)=4.77xxx10^(-10)m`.