Home
Class 12
PHYSICS
A cathode ray beam is bent into an arc o...

A cathode ray beam is bent into an arc of a circle of radius `0.02m` by a field of magnetic induction `4.55` milli tesla. The velocity of electron is (given `e=1.6xx10^(-19) c` and `m=1.9xx10^(-31)kg)`

A

`2xx10^(7) m//s`

B

`3xx10^(7)m//s`

C

`1.6xx10^(7)m//s`

D

`3.2xx10^(7)m//s`

Text Solution

Verified by Experts

The correct Answer is:
C
`v=(rBe)/m`
Promotional Banner

Topper's Solved these Questions

  • ATOMIC PHYSICS

    NARAYNA|Exercise LEVEL-III|80 Videos

  • ATOMIC PHYSICS

    NARAYNA|Exercise NCERT Based Questions|24 Videos

  • ATOMIC PHYSICS

    NARAYNA|Exercise LEVEL-I (C.W)|23 Videos

  • ALTERNATING CURRENT

    NARAYNA|Exercise LEVEL - II(H.W)|13 Videos

  • ATOMS

    NARAYNA|Exercise EXERCISE -4|47 Videos

Similar Questions

Explore conceptually related problems

A cathode ray beam is bent in a circle of radius 2 cm by a magnetic induction 4.5 xx10^(-3)" weber//m^2 ,The velocity of electron is

Calculate the gyro magnetic ratio of electron (given 1.6 xx10^(-19) C, m_r=9.1xx10^(-3) kg )

The de-Broglie wavelength of an electron is 66 nm. The velocity of the electron is [h= 6.6 xx 10^(-34) kg m^(2)s^(-1), m=9.0 xx 10^(-31) kg]

A photoelectron is moving with a maximum velocity of 10^(6) m//s . Given e=1.6xx10^(-19) c , and m=9.1xx10^(-31) kg , the stopping potential is

Light of wavelength 4000Å is incident on barium. Photoelectrons emitted describe a circle of radius 50 cm by a magnetic field of flux density 5.26xx10^-6 tesla . What is the work of barium in eV? Given h=6.6xx10^(-34)Js , e=1.6xx10^(-19)C, m_e=9.1xx10^(-31)kg.

An electron starts from rest and travels 0.9 m in an electric field of 200 V//m. After this , it enters a magnetic field at right angle to its direction of motion . If the radius of circular path of the electron is 9 cm, the magnetic field induction is (Given e= 1.6xx10^(-19) C, m=9xx10^(-31) g)

An electron of energy 1800 eV describes a circular path in magnetic field of flux density 0.4 T. The radius of path is (q = 1.6 xx 10^(-19) C, m_(e)=9.1 xx 10^(-31) kg)

The Velocity of electrons accelerated bt potential difference of 1xx10^(4) V (the charge of the electron is 1.6xx10^(-19) C and mass is 9.11xx10^(-31) kg) is

In an experiment, electrons are accelerated, from rest, by applying a voltage of 500V. Calculate the radius of the path if a magnetic field 100mT is then applied. [Charge of the electron =1.6xx10^(-19)C , Mass of the electron =9.1xx10^(-31) Kg]

In an experiment, electrons are accelerated, from rest, by applying a voltage of 500 V. Calculate the radius of the path if a magnetic field 100 mT is then applied. [Charge of the electron -1.6xx10^(-19)C Mass of the electron =9.1xx10^(-31)kg ]