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A charged oil drop fall with a terminal ...

A charged oil drop fall with a terminal velocity `V` in the absence of elcectric field . An electric field `E` keep keep the oil drop stationary in it . When the drop acquire a charge 'q' it moves up with same velocity. Find the initial charge on the drop.

A

`4q`

B

`2q`

C

`q`

D

`q//2`

Text Solution

Verified by Experts

The correct Answer is:
C
`E(q^(1)+q)=6pinrV_(0)+mg=2mg=2Eq`
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