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The de-Broglie wavelength of an electron...

The de-Broglie wavelength of an electron in the first Bohr orbit is

A

Equal to the circumference of the first orbit

B

`1//2th` circumference of the first orbit

C

`1//4th` circumference of the first orbit

D

`3//4th` circumference of the first orbit

Text Solution

Verified by Experts

The correct Answer is:
A
`mvr=(nh)/(2pi)=h/(mv):2pir=lambda`
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