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The maximum wavelength of Brackett serie...

The maximum wavelength of Brackett series of hydrogen atom will be _____`A^(@)`

A

`35,890`

B

`14,440`

C

`62,160`

D

`40,477`

Text Solution

Verified by Experts

The correct Answer is:
D
`RZ^(2)(1/n_(1)^(2)-1/n^(2_(2)))=1/lambda "where" n_(1)=4:n_(2)=5`
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