When an electron in the hydrogen atom in ground state absorb a photon of energy `12.1eV`, its angular momentum

Options

A. decrease by `2.11xx10^(-34)`
B. decreaseby`1.055xx10^(-34)`
C. increaseby `2.11xx10^(-34)`
D. increase by `1.055xx10^(-34)`

Answer

C

Explanation

After obsorbing a photon of energy 12.1eV electron jumps from ground state `(n=1)` to second excited state `(n=3) . "Therefore"` change in angular ,brgt momentum `DeltaL=L_(3)-L_(1) =3(h/(2pi)) -h/(2pi)=h/pi`
` =(6.6xx10^(-34))/(3.14)js=2.11xx10^(34)Js`