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Magnetic field at the center (at nucleus) of the hydrogen like atom `("atomic number" = z)` due to the motion of electron in nth orbit is proporional to

A

`n^(3)/Z^(5)`

B

`n^(4)/Z`

C

`Z^(2)/n^(3)`

D

`Z^(3)/n^(5)`

Text Solution

Verified by Experts

The correct Answer is:
D

`B_(n)=(mu_(0)I_(0))/(2r_(n))(or) B_(n)propI_(n)/(r_(n))prop((f_(n)))/r_(n)`
` B_(n)prop((v_(n)//r_(n)))/r_(n)propv_(n)/((r_(n))^(2)),prop((Z//n))/((n^(2)//Z)^(2))propZ^(3)/n^(5)`
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