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When the elecrton in the hydrogen atom j...

When the elecrton in the hydrogen atom jupms from `2nd` orbit to 1st orbit, the wavelength of radiation emitted is `lambda`. When the electrons jupms from `3rd` orbit to `1st` orbit, the wavelength of emitted radiation would be

A

`9/4lambda`

B

`4/9lambda`

C

`27/32lambda`

D

`32/27lambda`

Text Solution

Verified by Experts

The correct Answer is:
C
`1/lambda=RZ^2(1/n_(1)^(2)-1/n_(2)^(2))`
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