If elements of quantum number greater than `n` were not allowed , the number of possible element in nature would be ?

Options

A. `1/2n(n+1)`
B. `{(n(n+1))/(2)}^(2)`
C. `1/2n(n+1)(2n+1)`
D. `1/3n(n+1)(2n+1)`

Answer

D

Explanation

For each principal quantum number `n`, number of eelctron permitted equals the number of electron of element corresponding to the quantum number .
`{:(("Total,number"),("of elctrons")):} =Sigma2n^(2)=(n(n+1)(2n+1))/3`