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If we assume only gravitational attracti...

If we assume only gravitational attraction between protect and electron in hydrogen atom and the Bohr's quantization rule kto be allowed , then the expression for the ground state energy of the atom will be (the mass of proton is `M` and that of electron is `m`)

A

`(G^(2)M^(2)m^(2))/(h^(2))`

B

`(2pi^(2)G^(2)M^(2)m^(3))/(h^(2))`

C

`(2pi^(2)GM^(2)m^(3))/(h^(2))`

D

`(h^(2))/(G^(2)M^(2)n^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B

`mvr=(nh)/(2pi),(mv^(2))/r=(GMm)/r^(2)`
Energy `E=1/2mv^(2)-(GMn)/r`
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