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phtoelectron are emitted when `4000A^(0)` radiation is incident on a surface of work fuction `1.9eV`. these photoelectrons pass through a region has a- particles to form `He^(+)` ion, emitting a single photon in this process `He^(+)` ions thus formed are in their fourth excited state.
Energy released during during the combination of `He^(+)` ions is

A

`5.38eV`

B

`3.38eV`

C

`2.38eV`

D

`1.38eV`

Text Solution

Verified by Experts

The correct Answer is:
B
Differences of energy photoelectron recombines with a particle =`1.18-(-2.2)=3.38eV`
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