In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelangth in the Balmer series is:

Options

A. `3/23`
B. `5/27`
C. `7/29`
D. `9/31`

Answer

B

Explanation

`1/lambda=RZ^(2)(1/n_(1)^(2)-1/n_(2)^(2))`
for longest wave length in Lyman series `n_(1)=1, n_(2)` and for Balmar series `n_(1), n_(2)=3`