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The potential difference applying to an...

The potential difference applying to an X- ray tube is `5kV` and the current through it is `3.2mA`. Then the number of electrons striking the target per second is

A

`2xx10^(10)`

B

`5xx10^(16)`

C

`1xx10^(17)`

D

`4xx10^(15)`

Text Solution

Verified by Experts

The correct Answer is:
A
`i=((dn)/dt)eRightarrow3.2xx10^(-3)=((dn)/dt)(1.6xx10^(-19)) Rightarrow (dn)/(dt)=2xx10^(16)`
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