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Let A(0) be the area enclined by the orb...

Let `A_(0)` be the area enclined by the orbit in a hydrogen atom .The graph of in `(A_(0) //A_(1))` against `ln(n)`

A

will pass through the origin

B

will be certain point lyman on a straight line with slopes 4

C

will be a monotonically increasing nonlinear curve

D

will be a circle

Text Solution

Verified by Experts

The correct Answer is:
A, D
` A_(n)=pir_(n)^(2)=pi(r_(0)n^(2))^(2)=pir_(0)n^(4)` and `A_(1)=pir_(0)^(2)`
` ln"(A_(n))/(A_(1))=ln(n^(4))=4 lnn.`
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