Two electrons starting from rest are accelerated by equal potential difference.

Options

A. they will have kinetic energy
B. they will have same lineat momentum
C. they will have same de Broglie wave length
D. They will produce X-rays of same minimum wave length when they strikes different different targets.

Answer

A, B, C

Explanation

Kinetic energy of an electron is given by `K=1/2mv^(2)=eV`=same for both electron where v=speed of electron
V=potential difference
Linear momentum of two electron may be different, in direction but their magnitude i.e `mv=sqrt2mk` will be same . De-broglie wavelength is given by `lambda=h/(mv)`=same for both electrons
minimum wavelength of produced `x` rays is given by `lambda_(min)=(hc)/(eV)`=same for both electron .