The key feature of Bohr's spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton. We will extend this to a general rotational motion to find quantized rotational energy of a diatomic molecule assuming it to be rigid.The rule to be applied is Bohr's quantization condition.
In a `CO` molecule, the distance between `C (mass = 12 a. m. u ) and O (mass = 16 a.m.u)` where `1 a.m.u = (5)/(3) xx 10^(-27) kg , `is close to

Options

A. `2.4xx10(-10)m`
B. `1.9xx10^(-10)m`
C. `1.3xx10^(-10)m`
D. `4.4xx10^(-10)m`

Answer

C

Explanation

`r_(1)=(m_(2)d)/(m_(1)+m_(2))and r_(2)=(m_(1)d)/(m_(1)+m_(2))`
` I=m_(1)r_(1)^(2)+m_(2)r_(2)^(2) therefored=1.3xx10^(-10)m`