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29 electron are remove from Zn atom (Z=3...

`29` electron are remove from `Zn` atom `(Z=30)` by certain means . The minimum energy needed to remove the `30th` electron , will be :

A

`12.24keV`

B

`408keV`

C

`0.45keV`

D

`765keV`

Text Solution

Verified by Experts

The correct Answer is:
A
After removing 29 electrons, Zn atom will become `Zn^(+29) therefore E=13.6Z^(2)eV=12,24KeV`
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