The binding energy of the electron in the ground state of `He` atom is equal to `E_(0)=24.6 eV`. Find the energy required to remove both the electrons from the atom.

Options

A. `24.6eV`
B. `79.0eV`
C. `54.4eV`
D. `none of these

Answer

B

Explanation

The total energy required to make the electron free from nucleus is the sum of the energy required to separate the electron from the influence of each other and the energy required to separate the electron from the influence of nucleus , i.e total required energy energy=`BE` of electron in `He` atom + ionization energy of He atom =`(24.6+13.6xx2^(2))eV`
` (24.6+54.4)eV=79eV`