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A monochromatic radiation of wavelength ...

A monochromatic radiation of wavelength `lambda` is incident on a sample containig `He+`. As a result the Helium sample stars radiating. A part of this radiation is allowed to pass through a sample of atomic hydrogen gas in ground state. It is noticed that the hydrogen sample has stared emitting electrons whose maximum kinetic energy is `37.4 eV`.
`(hc = 12400 eV Å)`. Then `lambda` is

A

`275Å`

B

`243Å`

C

`656Å`

D

`386Å`

Text Solution

Verified by Experts

The correct Answer is:
B
Maximum energy of radiation incident on H-smple =`KE_(max)` of electron +13.6eV=51eV this energy corresponds to the transitions `n=4` to `n=1` in helium. For electron of the He to get excited to `n=4`, `lambda=(12400)/(51)=243A^(0)`
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