The difference between the longest wavlength line of the Balmar series and shortest wavelength line of the Lyman series for a hydrogen like atom (atomic number Z) equal to Deltalambda. The value of the Rydberg constant for the given atom si

Options

A. `5/(31)1/(Deltalambda.Z^(2))`
B. `5/36Z^(2)/(Deltalambda)`
C. `31/5 1/(Deltalambda.Z^(2))`
D. none

Answer

C

Explanation

`1/(lambda_(Lyman))=RZ^(2)(1-0)Rightarrow lambda_(Lyman)=1/(Rz^(2))`
` 1/lambda_(Balmer)=Rz^(2)(1/4-1/9)=Rz^(2)(5/36)Rightarrowlambda_("Balmer")=(36)/(5Rz)^(2),R=(31)/(5Deltalambdaz^(2))`