The energy ratio of two `k_(alpha)` photons obtined in `x` -ray from two metal targets of atomic numbes, `Z_(1)` and `Z_(2)` is ,

Options

A. `Z_(1)/Z_(2)`
B. `(Z_(1)/Z_(2))^(2)`
C. `((Z_(1)-1)/(Z_(2)-1))^(2)`
D. `sqrt(((Z_(1)-1))/((Z_(2)-1))`

Answer

C

Explanation

The energy of `K_(alpha)x`-rays photons is directly proportional to `(Z-1)^(2)`. The energy ratio of two `K_(a)` photons obtained in x-ray from two metal targets of atomic number `Z_(1)a` and `Z_(2)` is `((Z_(1)-1)/(Z_(2)-1))^(2)`