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Statement -1: In process of photoelectri...

Statement -1: In process of photoelectric emission , all emitted electrons donot have sam Kinetic energy
Statement-2: If radiation falling on photosensitive surface of a metal consits of different wavelength, then energy acquired by electrons absorbing photons of different wavelength shall be different.

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To analyze the given statements, we will break down the concepts of photoelectric emission and the energy of emitted electrons step by step. ### Step-by-Step Solution: 1. **Understanding Photoelectric Emission**: - When light (photons) strikes a metal surface, it can eject electrons from that surface. This phenomenon is known as photoelectric emission. - The energy of the incoming photons is given by the equation \(E = \frac{hc}{\lambda}\), where \(h\) is Planck's constant, \(c\) is the speed of light, and \(\lambda\) is the wavelength of the light. **Hint**: Remember that the energy of a photon is inversely proportional to its wavelength. 2. **Work Function**: - Each metal has a characteristic minimum energy required to release an electron, known as the work function (\(\phi\)). - The kinetic energy (KE) of the emitted electrons can be expressed as: \[ KE = E - \phi = \frac{hc}{\lambda} - \phi \] - This means that the kinetic energy of the emitted electrons depends on the energy of the incoming photons minus the work function of the metal. **Hint**: The work function is crucial in determining whether an electron can be emitted. 3. **Kinetic Energy Distribution**: - Not all emitted electrons will have the same kinetic energy. This is because: - Some electrons may start deeper within the metal and lose energy due to collisions with other particles before they escape. - Electrons that are closer to the surface will have more energy and thus higher kinetic energy when emitted. **Hint**: Consider the path and interactions of electrons within the metal before they are emitted. 4. **Statement 1 Analysis**: - Statement 1 claims that "In the process of photoelectric emission, all emitted electrons do not have the same kinetic energy." This is true due to the reasons discussed above. **Hint**: Think about the varying initial positions of electrons and their interactions. 5. **Statement 2 Analysis**: - Statement 2 states that "If radiation falling on the photosensitive surface of a metal consists of different wavelengths, then the energy acquired by electrons absorbing photons of different wavelengths shall be different." - This is also true because different wavelengths correspond to different photon energies, leading to different kinetic energies for the emitted electrons. **Hint**: Recall that energy and wavelength are related; shorter wavelengths have higher energy. 6. **Relationship Between Statements**: - While both statements are true, Statement 2 does not serve as a correct explanation for Statement 1. The variation in kinetic energy of emitted electrons is primarily due to their initial positions and interactions within the metal, rather than solely due to different wavelengths of incident light. **Hint**: Different factors can contribute to the same outcome; not all explanations are directly linked. ### Conclusion: - Both statements are true. - Statement 2 is not the correct explanation for Statement 1. ### Final Answer: - Both statements are correct, but Statement 2 is not the correct explanation of Statement 1.

To analyze the given statements, we will break down the concepts of photoelectric emission and the energy of emitted electrons step by step. ### Step-by-Step Solution: 1. **Understanding Photoelectric Emission**: - When light (photons) strikes a metal surface, it can eject electrons from that surface. This phenomenon is known as photoelectric emission. - The energy of the incoming photons is given by the equation \(E = \frac{hc}{\lambda}\), where \(h\) is Planck's constant, \(c\) is the speed of light, and \(\lambda\) is the wavelength of the light. ...
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