An gas of H-atom in excited state `n_(2)` absorbs a photon of some energy and jump in hiegher energy state `n_(1)`. Then it returns to ground state afer emitted six different wavelengths in emission spectrum. The energy of emitted photon is equal, less or greater than the energy of absorbed photon then `n_(1)` and `n_(2)` will be

Answer

B

Explanation

`0+1/2mv^(2)=(K(Q)e)/(10xx10^(-15))=(K(120e)e)/(10xx10^(-15)) 1/2xx5/3xx10^(-27)V^(2)=(9xx10^(9)xx120xx(1.6xx10^(-19))^(2))/(10xx10^(-15))`
` V=(9xx6xx10^(9)xx120xx2.56xx10^(-38))/(50xx10^-42)`
` V=sqrt(331.776xx10^(13))`
` lambda=h/(mv)`
` lambda=(4.2xx10^(-15)xx1.6xx10^(-19))/(5/3xx10^(-27)xxsqrt(331.776xx10^(13)))(4.2xx4.8xx10^(-34))/(57.6xx5xx10^(-21))=0.07xx10^(-13)`
` lambda=7xx10^(-15)=7fm`