Hydrogen aton in a sample are excited to `n = 5` state and it is found that photons of all possible wavelength are present in the emission spectra. The min imum number of hydrogen atom in the sample would be

Explanation

`Iomega=(nh)/(2pi)Rightarrowmr^(2)2pif=(nh)/(2pi)Rightarrowf=(nh)/(4pi^(2)mr^(2))r=r_(0)n^(2)and N=ft=8xx10^(6)`