Home
Class 12
PHYSICS
An electron starts from rest and travels...

An electron starts from rest and travels `0.9`m in an electric field of `200`V//m. After this , it enters a magnetic field at right angle to its direction of motion . If the radius of circular path of the electron is `9`cm, the magnetic field induction is (Given e=`1.6xx10^(-19)`C,
` m=9xx10^(-31)`g) `

A

`5xx10^9-4wb//m^(2)`

B

`5xx10^(-5)wb//m^(2)`

C

`5xx10^(-3)wb//m^(2)`

D

`5xx10^(-2)wb//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`v^(2)-U^(2)=2as,V^(2)=2(Eq)/mSRightarrowV=sqrt(2(Eq)/mS)r=(mV)/(Bq)RightarrowB=(mV)/(rq)`
Promotional Banner

Topper's Solved these Questions

  • ATOMIC PHYSICS

    NARAYNA|Exercise LEVEL-I (H.W)|22 Videos

  • ALTERNATING CURRENT

    NARAYNA|Exercise LEVEL - II(H.W)|13 Videos

  • ATOMS

    NARAYNA|Exercise EXERCISE -4|47 Videos

Similar Questions

Explore conceptually related problems

An electron moving at the speed of 10^(7) m/s , enters a magnetic field of induction 0.1 T at right angle to the velocity of electron . The radius of circular path followed by the electron is

Calculate the gyro magnetic ratio of electron (given 1.6 xx10^(-19) C, m_r=9.1xx10^(-3) kg )

An electron moving with a kinetic energy of 1.5 xx 10^(3) eV enters in a region of uniform magnetic field of induction 4 xx 10^(-3) Wb//m^(2) at right angles to the direction of motion of the electron . The radius of circular path of the electron in the magnetic field is

An electron of velocity 2.652 xx 10^(7) m/s enters a uniform magnetic field of direction of motion . The radius of its path is

An electron performs uniform circular motion in a region of magnetic field of induction 3 xx 10^(-3) Wb//m^(2) . If the radius of the circular path of the electron is 2 cm , then the momentum of the electron will be

An electron enters in a magnetic held of induction 2 m T with velocity of 1.8 xx 10^(7) m/s . The radius of circular path is

An electron of mass 'm' is accelerated through a potential difference of V and then it enters a magnetic field of induction B . Normal to the lines of force. Then the radius of the circular path is

A charged particle enters a magnetic field at right angles to the field. The field exists for a length equal to 1.5 times the radius of circular path of particle. The particle will be deviated from its path by

An electron of energy 1800 eV describes a circular path in magnetic field of flux density 0.4 T. The radius of path is (q = 1.6 xx 10^(-19) C, m_(e)=9.1 xx 10^(-31) kg)

Electron at rest are accelerated by a potential of V volt. These electrons enter the region of space having a uniform, perpendicular magnetic induction field B. the radius of the path of the electrons inside the magnetic field is