The total number of air molecules in a room of capacity `20 m^(3)` at a temperature of `27^(@)C` and 1 atm pressure is

Explanation

Given, volume (V)=`20m^(3)`
Temperature (T)=27+273=300K
Pressure (P)=1 atm=`1.01xx10^(5) Pa`
Total number of air molecules `N=(PV)/(K_(B)T)`
`=(1.01xx10^(5)xx20)/(1.38xx10^(-23)xx300)=4.87xx10^(26)`