Two moles of an idel gas X occupying a volume V exerts a pressure P. The same pressure is exerted by one mole of another gas Y occupying a volume 2V. (if the molecular weight of Y is 16 times the molecular weight of X), find the ratio of the 'rms' speeds of the molecules of X and Y.

Explanation

`v_(rms)=sqrt((3PV)/(muM))(because (m)/(M)=mu)`
`((V_(rms))_(1))/((V_(rms))_(2))=sqrt((V_(1))/(V_(2))(mu_(2))/(mu_(1))(M_(2))/(M_(1)))rArr((V_(rms))_(1))/((V_(rms))_(2))`
`=sqrt((V)/(2V)((1)/(2))(16)/(1))=2`