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The diameter of a gas molecule is 2.4 xx...

The diameter of a gas molecule is `2.4 xx 10^(-10) m`. Calculate the mean free path at NTP. Given Boltzmann constant `k = 1.38 xx 10^(-23)` `J molecule^(-1) K^(-1)`.

A

`2.45xx10^(-10)m`

B

`2.45xx10^(-7)m`

C

`1.45xx10^(-7)m`

D

`1.45xx10^(-10)m`

Text Solution

Verified by Experts

The correct Answer is:
C
`n=(N)/(V)=(P)/(KT)=2.69xx10^(25)m^(-3)`
`lambda=(1)/(sqrt(2)pid^(2)n)`
`=1.45xx10^(-7)m`
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