In a cyclic process shown in the figure an ideal gas is adiabatically taken from `B`to`A`, the work done on the gas during the process `B`to`A` is `30,J` when the gas is taken from `A` to `B` the heat absorbed by the gas is `20 J` Then change in internal energy of the gas in the process `A` to `B` is :

Explanation

`W_(BA)=-30J,Q_(BA)=0,DeltaU_(BA)=-W_(BA)=30J`
Now, `DeltaU_(AB)=-DeltaU_(BA)=-30J`