When 5 moles of an ideal gas is compressecd isothermally, its volume decreases from 5 litre to 1 litre. If the gas is at `27^(@)C`, find the work done on the gas `("log"_(10)((1)/(5))=-0.6990)`.

Explanation

In the case of 'n' moles, work done on the gas
`W=nRT "log"_(e)((V_(2))/(V_(1)))`
`W=nRTxx2.3026xx"log"_(10)((V_(2))/(V_(1)))`
`thereforeW=5xx8.314xx300xx2.3026xx"log"_(10)((1)/(5))`
`=5xx8.314xx300xx2.3026xx(-0.6990)`
`=-2.007xx10^(4)J`