A monoatomic gas undergoes a process given by `2dU+3dW=0`, then what is the process

Explanation

To solve the problem regarding the process undergone by a monoatomic gas described by the equation \(2dU + 3dW = 0\), we will follow these steps:

### Step-by-Step Solution:

1. **Understanding the Given Equation**:
The equation \(2dU + 3dW = 0\) can be rearranged to express \(dW\) in terms of \(dU\):
\[
3dW = -2dU \implies dW = -\frac{2}{3}dU
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