How much will the temperature of 100g of...

How much will the temperature of 100g of water be rised by doing 4200 J of work in stirring the water?

`0.01^(@)C`

`0.1^(@)C`

`1^(@)C`

`10^(@)C`

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`W=JHrArrW=JmSDeltatheta`

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4200 J of work is required for

Water of volume 4L in a closed container is heated with a coil of 2 kW. While water is heated, the container loses energy at a rate of 120 J/s. In how much time will the temperature of water rise from 27^(@)C to 77^(@)C ? (Specific heat of water is 4.2 kJ/kg and that of the container is negligible).

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A piece of ice of mass 100 g and at temperature 0^@ C is put in 200 g of water of 25^@ C . How much ice will melt as the temperature of the water reaches 0^@ C ? (specific heat capacity of water =4200 J kg^(-1) K^(-1) and latent heat of fusion of ice = 3.4 xx 10^(5) J Kg^(-1) ).

How much time heater will take to increase the temperature of 100g water by 50^(@)C if resistance of heating coat is 484Omega and supply voltage is 220V a.c.

A vessel containing 100 g ice at 0^(@)C is suspended in a room where temperature is 35^(@)C . It was found that the entire ice melted in 10 hour. Now the same vessel containing 100 g of water at 0^(@)C is suspended in the same room. How much time will it take for the temperature of water to rise to 0.5^(@)C . Neglect the heat capacity of the vessel. Specific heat of water and specific latent heat of fusion of ice are 1 cal g^(-1) .^(@)C^(-1) and 80 cal g^(-1) respectively.

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A piece of ice of mass of 100g and at temperature 0^(@)C is put in 200g of water of 25^(@) How much ice will melt as the temperature of the water reaches 0^(@)C ? The specific heat capacity of water = 4200 J kg ^(-1)K^(-1) and the latent heat of ice = 3.36 xx 10^(5)J kg^(-1)

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