m' grams of a gas of a molecular weight M is flowing in a isolated tube with velocity 2v. If the gas flow is suddenly stopped the rise in its temperature is (`gamma=` ratio of specific heats, R=universal gas constant, J=Mechanical equivalent of heat)

Options

A. `(2Mv^(2)(gamma-1))/(RJ)`
B. `(mv^(2)(gamma-1))/(M2RJ)`
C. `(mv^(2)gamma)/(2RJ)`
D. `(Mv^(2)gamma)/(2RJ)`

Answer

A

Explanation

`W=jQrArr(1)/(2)m(2v)^(2)=JnC_(v)DeltaT`