An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are `Q_1=5960J, Q_2=-5585J, Q_3=-2980J and Q_4=3645J`, respectively. The corresponding quantities of work involved are `W_1=2200J, W_2=-825J, W_3=-1100J and W_4` respectively.
(1) Find the value of `W_4`.
(2) What is the efficiency of the cycle

Options

A. `1315J,10%`
B. `275J,11%`
C. `765J,10.82%`
D. `675J,10.82%`

Answer

C

Explanation

Cyclic process `DltaU=0, Q_("net")=W_("net")`
`Q_(1)+Q_(2)+Q_(3)+Q_(4)=W_(1)+W_(2)+W_(3)+W_(4)`
Efficiency `eta=`
`("Total workdone in cycle")/("Heat absorbed by the gas during the cycle")xx100`
`eta=((W_(1)+W_(2)+W_(3)+W_(4))/(Q_(1)+Q_(4)))xx100`