Consider an ideal gas confined in an isolated closed chamber. As the gas undergoes an adiabatic expansion, the average time of collision between molecules increase as `V^q`, where V is the volume of the gas. The value of q is : `(gamma=(C_p)/(C_v))`

Options

A. `(3gamma+5)/(6)`
B. `(3gamma-5)/(6)`
C. `(gamma+1)/(2)`
D. `(gamma-1)/(2)`

Answer

C

Explanation

`tau=(gamma)/(V_("max"))=(1)/(sqrt(2)pid^(2)((N)/(V))sqrt((3RT)/(M)))`
`tauprop(V)/sqrt(T)`
`TV^(gamma-1)=k`
`taupropV^((gamma+1)/(2))`