A block is released on an smooth inclined plane of inclination `theta`. After how much time it reaches to the bottom of the plane?

Explanation

`bot^(ar)` to the plane`:` `N-mgcostheta=0`
`N=mgcostheta`
Along the plane `:mgsintheta=ma`
`a=gsintheta`
Acceleration of the block along the plane `=gsintheta`

`sintheta=(h)/(l)rArrl=(h)/(sintheta)`
Along the plane `:a=gsintheta`
`s=ut+(1)/(2)gsinthetat^(2)`
`(h)/(sintheta)=0+(1)/(2)gsinthetat^(2)`
`t=(1)/(sintheta)sqrt((2h)/(g))`