A block of mass `M` is attached to a uniform rope of mass `m`. This arrangement is pulled by applying a force `F` at the rope as shown. Find the tension in the rope (a) at the junction of the rope and the block (b) at the mid point of the rope.

Explanation

`F=(M+m)a`
`rArra=(F)/(M+m)`
(a) At the junction of the block and the rope`:`
`T=Ma=(MF)/(M+m)`
(b) At the mid-point of the rope
`T'=(M+(m)/(2))a`
`=((2M+m)/(2))((F)/(M+m))
If `m=0`
`T=T'=F`
If the rope is light, tension in the rope at each point is same.