Two blocks of masses `m` and `2m` are placed on a smooth horizontal surface as shown in the figure. Find the acceleration of each block and normal reaction between two blocks if a horizontal force `F_(0)` is applied on (a) `m` and (b) `2m`

Explanation

Here, each block moves same distance in equal time, hence their acceleration is same.

`F_(0)=(m+2m)arArra=(F_(0))/(3m)`

`N=2ma=2mxx(F_(0))/(3m)=(2F_(0))/(3)`
`F_(0)=(m+2m)arArra=(F_(0))/(3m)`

`N=ma=mxx(F_(0))/(3m)=(F_(0))/(3)`