A block of mass `m` is attached to a chain as shown in the diagram. Find the tension in each of the three chains. The ring and chains are light.

Explanation

Block`:`

`T_(1)-mg=0rArrT_(1)=mg`
`uarr:T_(2)cos30^(@)-T_(1)=0`
`T_(2)=(T_(1))/(cos30)=(mg)/(sqrt(3//2))=(2mg)/(sqrt(3))`
`rarr:T_(2)sin30^(@)-T_(3)=0`
`T_(3)=T_(2)sin30^(@)=(2mg)/(sqrt(3)).(1)/(2)=(mg)/(sqrt(3))`
The tension in three chains are `mg.(2mg)/(sqrt(3))` and `(mg)/(sqrt(3))`.