Two masses `m_(1)` and `m_(2)` are connected by a light string passing over a smooth pulley. When set free `m_(1)` moves downward by 2 m in 2 s. The ratio `m_(1)//m_(2)` is

Options

A. `9//7`
B. `11//9`
C. 13/11
D. 15/13

Answer

B

Explanation

`a=((m_(1)-m_(2))g)/((m_(1)+m_(2)))`
`x=(1)/(2)at^(2)`
`2=(1)/(2)a(2)^(2)`
`a=1m//s^(2)`
`((m_(1)-m_(2))g)/((m_(1)+m_(2)))=1`
`10m_(1)-10m_(2)=m_(1)+m_(2)`
`9m_(1)=11m_(2)`
`(m_(1))/(m_(2))=(11)/(9)`