[" 5.If "ABCDEF" is a regular heragon,prove that "],[qquad vec Lambda C+vec AD+vec EA+vec FA=3vec AB]

If ABCDEF is a regular hexagon, prove that vec(AC)+vec(AD)+vec(EA)+vec(FA)=3vec(AB)

If ABCDEF is a regular hexagon, prove that vec(AC)+vec(AD)+vec(EA)+vec(FA)=3vec(AB)

If ABCDEF is a regular hexagon,them vec AD+vec EB+vec FC equals 2vec AB b.vec 0 c.3vec AB d.4vec AB

If ABCDEF is a regular hexagon with vec AB=vec a and vec BC=vec b, then vec CE equals

In Fig. ABCDEF is a ragular hexagon. Prove that vec(AB) +vec(AC) +vec(AD) +vec(AE) +vec(AF) = 6 vec(AO) .

If ABCDEF is a regular hexagon , then A vec D + E vec B + F vec C equals

In a regular hexagon ABCDEF,vec AE

ABCDEF is a regular hexagon. Express the vectors vec (CD) , vec (DE) , vec (EF) , vec (FA) , vec (CE) in terms of vec (AB) and vec (BC) .

If ABCDEF is a regular hexagon then vec AD + vec EB + vec FC =

If ABCDEF is a regular hexagon with vec(AB) = veca and vec(BC)= vecb, then vec(CE) equals