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A block of mass M is pulled along a hori...

A block of mass `M` is pulled along a horizontal frictionless surface by a rope of mass `m` . Force P is applied at one end of rope. The force which the rope exerts on the block is:

A

`(P)/(M-m)`

B

`(PM)/(M-m)`

C

`(Pm)/(M-m)`

D

`(PM)/(M+m)`

Text Solution

Verified by Experts

The correct Answer is:
D


`P=(M+m)arArr=(P)/(M+m)`

`T=Ma=(PM)/(M+m)`
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