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A man of mass m stands on a frame of mas...

A man of mass m stands on a frame of mass M. He pulls on a light rope, which passes over a pulley. The other end of the rope is attached to the frame. For the system to be in equilibrium, what force must the man exert on the rope?

A

`((M+m)g)/(2)`

B

`(M+m)g`

C

`(M-m)g`

D

`(M+2m)g`

Text Solution

Verified by Experts

The correct Answer is:
A
(1) Man:

T+N=mg (i)
Frame:
T-N=Mg (II)
`T=((M+m)g)/(2)`
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