A man weighs 80kg . He stands on a weigh...

A man weighs `80kg` . He stands on a weighing scale in a lift which is moving upwords with a uniform acceleration of `5m//s^(2)` . What would be the reading on the scale?

400 N

800 N

1200 N

zero

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Verified by Experts

The correct Answer is:

Weight is indicated by normal reaction.

`N_(0)-Mg=Ma`
`N_(0)=W=M(g+a)`
=80(10+5)
=1200N

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