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An elevator car whose floor to ceiling d...

An elevator car whose floor to ceiling distance is equal to `2.7 m` starts ascending with constant acceleration `1.2 m//s^(2)`, 2 sec after the start a bolt begins falling from the ceiling of the car. Answer the following question `(g=9.8 m//s^(2))`
The bolt's free fall time is

A

`sqrt(0.54)s`

B

`sqrt(6)s`

C

0.7 s

D

1 s

Text Solution

Verified by Experts

The correct Answer is:
C
`h=(1)/(2)(g+a)t^(2)`
`t=sqrt((2h)/(g+a))=sqrt((2xx2.7)/(11))0.7s`
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