The block is in equilibrium

`(i) T_(1)=(mgcosbeta)/(sin(alpha+beta))" "(ii)T_(2)=(mgcosalpha)/(sin(alpha+beta))`
`(iii)T_(1)/T_(2)=(cosbeta)/(cosalpha)" "(iv)T_(1)/T_(2)=(cosalpha)/(cosbeta)`

Options

A. (i),(ii)
B. (i),(ii),(iii)
C. (ii),(iii)
D. (iii),(iv)

Answer

B

Explanation

`(T_(1))/(sin(90+beta))=(T_(2))/(sin(90+alpha))=(mg)/(sin[180-(alpha+beta)])`
`(T_(1))/(cosbeta)=(T_(2))/(cosalpha)=(mg)/(sin(alpha+beta))`
`T_(1)=(mgcosbeta)/(sin(alpha+beta)),T_(2)=(mgcosalpha)/sin(alpha+beta)`