A uniform magnetic field `B` exists in a direction perpendicular to the palne of a square frame made of copper wire. The wire has a total length of `40cm` . The magnetic field changes with time at a steady rate `(dB//dt)=0.02T//sec` . Find the current induced in the frame. Resistance of wire `=I0Omega`

Explanation

Total length of wire `=40cm` i.e. each side of square `=10cm`
Flux passing through frame
`phi=BA=Bl^(2)`
`e=(dphi)/(dt)l^(2)=0.02xx(0.1)^(2)=2xx10^(-4)V`
`I=(e)/(R)=(2xx10^(-4))/(10)=2xx10^(-5)A`