The horizontal component of the earth's magnetic field at a place is `3.0 X 10^(-4) T` and the dip is `53^@`. A metal rod of length 25cm is placed in the north - south direction and is moved at a constant speed of 10cm s^(-1) towards east. Calculate the emf induced in the rod.

Explanation

The velocity `v` , length `l` and `B_(v)` (vertical component of earth magnetic field) are mutually perpendicular
`e=B_(v)Vl ( :. Tanphi=(B_(v))/(B_(h)))`
`=B_(h)tanphivl`
`=3xx10^(-4)tan53^(@)xx0.1xx0.25`
`=3xx10^(-4)xx(4)/(3)xx25xx10^(-3)=10^(-5)V`
No induced emf due to `B_(h)` (horizontal component of earth magnetic field) because it is parallel to length of rod.