Calculate the self-inductance of a coil of `100` turns, if a current of `2A` gives rise to magnetic flux of `50muWb` through the coil. Also calculate the magentic energy stored in the medium surrounding the coil for the above value of current.

Explanation

`Nphi=Li`
`100xx50xx10^(-6)=Lxx2`
`L=2.5xx10^(-3)H=2.5mh`
`U=(1)/(2)Li^(2)=(1)/(2)xx2.5xx10^(-3)xx(2)^(2)`
`=5xx10^(-3)J`